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Limits and DerivativesIntuitive Idea of Derivatives

Reading time: ~15 min

Let us slow the pebble down and look at the numbers the speed trap was using. Experiments confirm that a body dropped from a height falls s = 4.9t^2 metres in the first t seconds (as long as air resistance is small). Table 12.1 lists the distance fallen at various times.

Table 12.1

t (s)s (m)
00
14.9
1.511.025
1.815.876
1.917.689
1.9518.63225
219.6
2.0520.59225
2.121.609
2.223.716
2.530.625
344.1
478.4

We want the velocity at exactly t = 2 seconds. All that the table can give directly is an average velocity: the distance travelled in a time interval, divided by the length of the interval. Between the times t_1 and t_2,

\text{average velocity} = \dfrac{s(t_2) - s(t_1)}{t_2 - t_1}

In the first two seconds the body falls from 0 m to 19.6 m, so its average velocity is \dfrac{19.6 - 0}{2 - 0} = m/s.

Between t = 1 and t = 2 it falls from 4.9 m to 19.6 m, so its average velocity is \dfrac{19.6 - 4.9}{2 - 1} = m/s.

The second interval is shorter and hugs t = 2 more closely, so its average is a better stand-in for the velocity at t = 2. Shorter still should be better still.

Table 12.2 uses intervals that end at 2 seconds and start at t_1, closer and closer to 2. Table 12.3 uses intervals that start at 2 seconds and end at t_2, closer and closer to 2. Fill in the missing entries from Table 12.1.

Table 12.2 — from t_1 to 2 s

t_1v (m/s)
09.8
114.7
1.517.15
1.818.62
1.9
1.9519.355
1.9919.551

Table 12.3 — from 2 s to t_2

t_2v (m/s)
429.4
324.5
2.522.05
2.220.58
2.1
2.0519.845
2.0119.649

Read both tables from top to bottom. In Table 12.2 the average velocities as t_1 moves up towards 2, and in Table 12.3 they as t_2 moves down towards 2.

So the velocity at t = 2 must lie between the last entries, 19.551 m/s and 19.649 m/s: the same squeeze you saw in the speed trap. On physical grounds the two sequences must close in on one common value, assuming nothing dramatic happens in the last hundredth of a second. That value is the instantaneous velocity at t = 2.

Velocity is the rate of change of distance. So from the distances at many instants we have estimated the rate at which the distance changes at one instant. We say that the derivative of the distance function s = 4.9t^2 at t = 2 lies between 19.551 and 19.649.

Note

A car's speedometer does exactly this. It cannot wait a minute to see how far the car goes, so it measures the distance covered in a tiny sliver of time and divides. Whenever you read a speedometer, you are reading a derivative.

From Chords to the Tangent

The same squeeze has a picture. Fig. 12.1 plots the distance s against the time t: the curve s = 4.9t^2, with the point A at t = 2.

Pick a later time 2 + h and its point B on the curve. Go across from A to C, then up from C to B. AC is the time interval h, and CB is the distance fallen in that interval, s(2 + h) - s(2). So the average velocity over the interval, \dfrac{\text{CB}}{\text{AC}}, is exactly the slope of the chord AB.

Bring B closer to A, one step at a time, and watch the slope of the chord. The earlier chords stay behind, faded.

Fig. 12.1 — s = 4.9t^2. The chords AB settle onto the tangent at A as B comes closer.

Label the successive positions \text{B}_1, \text{B}_2, \text{B}_3, \ldots, with intervals h_1, h_2, h_3, \ldots shrinking to zero. The ratios \dfrac{\text{C}_1\text{B}_1}{\text{AC}_1}, \dfrac{\text{C}_2\text{B}_2}{\text{AC}_2}, \dfrac{\text{C}_3\text{B}_3}{\text{AC}_3}, \ldots are the average velocities, so they approach the same limit, while the chords approach the tangent to the curve at A. So the instantaneous velocity at t = 2 equals the of the tangent to the curve s = 4.9t^2 at A.

Two views of one idea: the derivative is a rate of change, and it is also the slope of a tangent. We will come back to both once we know exactly what a limit is.

Speed Round: Average or Instant?

Each body below falls (or rolls) a distance s = kt^2 metres in t seconds, for some number k. Some questions ask for the average speed over a window, and some for the speed at one instant. Look for the pattern in the instant answers: it is the first derivative rule of this chapter in disguise.

Get five right to move on.

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